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练习

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#1 Created at ... [Delete] [Delete and Lock User]
def is_palindrome(n):
    s = str(n)
    if len(s)%2==0:
        return s[:len(s)//2] == str(n)[len(s)//2:]
    else:
        return s[:len(s)//2] == str(n)[len(s)//2+1:]

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