i = math.sqrt(b*b-4*a*c)
if i < 0:
reurn ('无解')
else:
x1 = (-b+i)/(2*a)
x2 = (-b-i)/(2*a)
return x1,x2
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浪漫的丶差不多
i = math.sqrt(b*b-4*a*c)
if i < 0:
reurn ('无解')
else:
x1 = (-b+i)/(2*a)
x2 = (-b-i)/(2*a)
return x1,x2