第三题
Topic source
#补充一下 前面还有：
from functools import reduce
DIGITS = {'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9}
def char2num(s):
return DIGITS[s]
- 1
#补充一下 前面还有：
from functools import reduce
DIGITS = {'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9}
def char2num(s):
return DIGITS[s]
___iFancy
零基础入门也有好几天了 也交个作业吧：
def str2float(s):
def f1(x,y):
return x*10+y
def f2(x,y):
return x/10+y
for i in range(len(s)):
if s[i] == '.':
n = i
integer=reduce(f1,map(char2num,s[:n]))
decimal=reduce(f2,map(char2num,s[-1:n:-1]))
return integer+decimal/10