# 利用闭包返回一个计数器函数,每次调用它返回递增整数 def createCounter(): fs = [] def counter(): # 每次都在后面加上当前list的长度+1的元素[1] fs.append(len(fs) + 1) # 返回最后一位元素 1 return fs[-1] return counter # 测试: counterA = createCounter() print(counterA(), counterA(), counterA(), counterA(), counterA()) # 1 2 3 4 5 counterB = createCounter() if [counterB(), counterB(), counterB(), counterB()] == [1, 2, 3, 4]: print('测试通过!') else: print('测试失败!')
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唯情恋昉