#高阶函数-map/reduce 作业

''''

#作业1

# -*- coding: utf-8 -*-

def normalize(name):

    return name[0].upper() + name[1:].lower()

L1 = ['adam', 'LISA', 'barT']

L2 = list(map(normalize, L1))

print(L2)

'''

'''

#作业2

# -*- coding:utf-8 -*-

from functools import reduce

def prod(L):

    return reduce(lambda x, y : x * y, L)

print('3 * 5 * 7 * 9 =', prod([3, 5, 7, 9]))

if prod([3, 5, 7, 9]) == 945:

    print('测试成功!')

else:

    print('测试失败!')

'''

'''

#作业3

# -*- coding: utf-8 -*-

from functools import reduce

def str2float(s):

    list1 = s.split('.')

    n1 = reduce(lambda x, y: 10 * x + y, map(int, list1[0]))

    n2 = reduce(lambda x, y: (x * 0.1 + y) , map(int,list1[1][::-1])) 

    # 注意list1要倒置，另外一种方法可以在函数返回利用长度乘以0。1乘方

    return n1 + n2 * 0.1

print('str2float(\'123.456\') =', str2float('123.456'))

if abs(str2float('123.456') - 123.456) < 0.00001:

    print('测试成功!')

else:

    print('测试失败!')

'''