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既满足log又满足log（‘te'x't’）

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流逝的仲夏夜之梦

#1 Created at ... [Delete] [Delete and Lock User] 
import functools

def log(name):
    if callable(name):
        @functools.wraps(name)
        def wrapper(*args, **kw):
            print('begin call', name.__name__)
            f = name(*args, **kw)
            print('end call', name.__name__)
            return f
        return wrapper
    else:
        def decorator(func):
            @functools.wraps(func)
            def wrapper(*args, **kw):
                print('begin call', name)
                f = func(*args, **kw)
                print('end call', name)
                return f
            return wrapper
        return decorator

萬萬沒想到516

#2 Created at ... [Delete] [Delete and Lock User]

你应该加上return wrapper，你不测试下函数的吗，不加都不会出结果

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