Discuss / Python / 笨方法:转化为list,倒序排列后比较值是否相同

笨方法:转化为list,倒序排列后比较值是否相同

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dudefitslol

#1 Created at ... [Delete] [Delete and Lock User]

#最佳答案的切片取倒序的方法太巧妙了。

def is_palindrome(n):

    s1 = [m for m in str(n)] #将整数转化为序列list

    s1.reverse() #倒序排列list

    s2 = [m for m in str(n)]

    return s1 == s2 #比较两个list中对应元素是否相等


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