x1=(-b+math.sqrt(b*b-4*a*c))/2/a
x2=(-b-math.sqrt(b*b-4*a*c))/2/a
return x1,x2
pass
Sign in to make a reply
妖夜第七瞳
x1=(-b+math.sqrt(b*b-4*a*c))/2/a
x2=(-b-math.sqrt(b*b-4*a*c))/2/a
return x1,x2
pass