def pi(N): #计算pi的值 # step 1: 创建一个2*N的自然数序列 natures = itertools.count(1) nature = list(itertools.takewhile(lambda x: x <= 2*N, natures)) odd = [] # step 2: 取该序列的奇数项: 1, 3, 5, 7, 9, ..., 2*N-1. for i in nature: if i % 2 == 1 : odd.append(i) # step 3: 添加正负符号并用4除: 4/1, -4/3, 4/5, -4/7, 4/9, ... sumlist = [] for i in range(N): if i % 2 == 0 : sumlist.append(4/odd[i]) else: sumlist.append(-4/odd[i]) # step 4: 求和: pi = sum(sumlist) return pi
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