第一题:
def normalize(name):
result = name[0].upper() + name[1:].lower()
return result
第二题:
def prod(L):
def multiply(x, y):
return x * y
return reduce(multiply, L)
第三题:
def integer(x, y):
return x * 10 + y
def point(x, y):
return x / 10 + y
DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}
def char2num(s):
return DIGITS[s]
loc = s.find('.')
s1 = s[:loc]
s2 = s[loc + 1:]
s2 = s2[::-1]
int = reduce(integer, map(char2num, s1))
float = reduce(point, map(char2num, s2))
return int + float /10
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用户7010476157
第一题:
def normalize(name):
result = name[0].upper() + name[1:].lower()
return result
第二题:
def prod(L):
def multiply(x, y):
return x * y
return reduce(multiply, L)
第三题:
def integer(x, y):
return x * 10 + y
def point(x, y):
return x / 10 + y
DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}
def char2num(s):
return DIGITS[s]
loc = s.find('.')
s1 = s[:loc]
s2 = s[loc + 1:]
s2 = s2[::-1]
int = reduce(integer, map(char2num, s1))
float = reduce(point, map(char2num, s2))
return int + float /10