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用户5307799436

#1 Created at ... [Delete] [Delete and Lock User] 
def createCounter():
    x = 0
    def counter():
        nonlocal x
        while True:
            x = x + 1
            break
        return x
    return counter



def createCounter():
    x = [0]
    def counter():
        x[0] += 1
        return x[0]
    return counter

第二次执行的时候,x[0]就等于1了吗,不是x[0] = 0么?

用户7449777361

#2 Created at ... [Delete] [Delete and Lock User]

#?头保命，我也是萌新

利用步入观察发发现，把counter返回给couterA以后，以后每次调用counterA，只会调用counter函数内部内容。所以就是 x = [0]那步，好像都不走了。

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