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交作业

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活力老汤

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    for i in range(len(s)):

        if s[i]=='.':

            s1=s[:i]

            s2=s[i+1:]       

    def fn(x, y):

        return x * 10 + y

    def char2num(s):

        digits = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}

        return digits[s]

    ss1=reduce(fn, map(char2num, s1))

    ss2=reduce(fn, map(char2num, s2))

    return ss1+float(ss2/(10**len(s2)))


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