import math
a=float(input('plase enter the number a:'))
b=float(input('plase enter the number b:'))
c=float(input('plase enter the number c:'))
n=b*b-4*a*c
def quadratic(a, b, c):
if a==0:
x=-c/b
print('一元一次方程:',x)
return elif n>0:
x1=(-b+math.sqrt(n))/2*a
x2=(-b-math.sqrt(n))/2*a
print('方程有两个解:',x1,x2)
return elif n==0:
x=-b/(2*a)
print('方程只有一个解',x)
return else:
return'方程无解'print(quadratic(a,b,c))
shishenyueshang