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通过迭代的方式，依次作比较

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石头王国精挑细选的石头

#1 Created at ... [Delete] [Delete and Lock User] 
def findMinAndMax(L):
    if L != []:
        max,min = L[0],L[0]
        for i in L:
            if i >= l:
                max = i
        for j in L:
            if j <= n:
                min = j
        return (min,max)
    else:
        return (None,None)
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