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打卡

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第一题

    return name[:1].upper() + name[1:].lower()

第二题

    return reduce(lambda x, y: x* y, L)

第三题

# -*- coding: utf-8 -*-from functools import reducedef str2float(s):    digits = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}    def char2num(s):        return digits[s]    return reduce(lambda x, y: x * 10 + y, map(char2num, s[:s.find(".")])) + \           reduce(lambda x, y: x * 0.1 + y, map(char2num, s[:s.find("."):-1])) * 0.1print('str2float(\'123.456\') =', str2float('123.456'))if abs(str2float('123.456') - 123.456) < 0.00001:    print('测试成功!')else:    print('测试失败!')
# -*- coding: utf-8 -*-from functools import reducedef str2float(s):    digits = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}    def char2num(s):        return digits[s]    return reduce(lambda x, y: x * 10 + y, map(char2num, s[:s.find(".")])) + \           reduce(lambda x, y: x * 0.1 + y, map(char2num, s[:s.find("."):-1])) * 0.1print('str2float(\'123.456\') =', str2float('123.456'))if abs(str2float('123.456') - 123.456) < 0.00001:    print('测试成功!')else:    print('测试失败!')

测试一下代码怎么样不会塌

from functools import reducedef str2float(s):    digits = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}    def char2num(s):        return digits[s]    return reduce(lambda x, y: x * 10 + y, map(char2num, s[:s.find(".")])) + \           reduce(lambda x, y: x * 0.1 + y, map(char2num, s[:s.find("."):-1])) * 0.1

继续测

    digits = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}
    def char2num(s):
        return digits[s]
    return reduce(lambda x, y: x * 10 + y, map(char2num, s[:s.find(".")])) + \
           reduce(lambda x, y: x * 0.1 + y, map(char2num, s[:s.find("."):-1])) * 0.1print('str2float(\'123.456\') =', str2float('123.456'))

似乎太长就会踏?


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