def is_palindrome(n):
s = str(n)
s = s[::-1]
number = int(s)
return n - number == 0
--------------------------------一开始的i想法------------------------------------------------
return int(str(n)[::-1]) - n == 0
----------------------------------------然后压缩行数------------------------------------
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榭柯靳
def is_palindrome(n):
s = str(n)
s = s[::-1]
number = int(s)
return n - number == 0
--------------------------------一开始的i想法------------------------------------------------
def is_palindrome(n):
return int(str(n)[::-1]) - n == 0
----------------------------------------然后压缩行数------------------------------------