Discuss / Python / 交作业
Back

交作业

Topic source

回风哥哥

#1 Created at ... [Delete] [Delete and Lock User]

第一题：

def normalize(name):
    return f'{name[0].upper()}{name[1:].lower()}'

第二题：

def prod(L):
    return reduce(lambda x, y: x * y, L)

第三题：

def str2float(s):
    """字符串转浮点型"""

    def char2num(c):
        """字符转数字"""

        digists = {'0':0, '1':1, '2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9}
        return digists[c]

    def profix_num(l):
        """数字列表转数字"""

        return reduce(lambda x, y: x * 10 + y, l)

    def subfix_num(l):
        """数字列表转小数"""

        return reduce(lambda x, y: x * 0.1 + y, l) * 0.1

    pro_str, sub_str = s.split('.')[0], s.split('.')[1]  # 获得整数部分和小数部分字符串
    pro_num = profix_num(map(char2num, pro_str))  # 获得整数部分
    sub_num = subfix_num(map(char2num, sub_str[::-1]))  # 获得小数部分
    return pro_num + sub_num

回风哥哥

#2 Created at ... [Delete] [Delete and Lock User]

第三题精简了一下：

def str2float(s):
    """字符串转浮点型"""

    def char2num(c):
        """字符转数字"""

        digists = {'0':0, '1':1, '2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9}
        return digists[c]

    s_split = s.split('.')
    pro_num = profix_num(map(char2num, s_split[0]))  # 获得整数部分
    sub_num = subfix_num(map(char2num, s_split[1][::-1]))  # 获得小数部分
    return pro_num + sub_num

回风哥哥

#3 Created at ... [Delete] [Delete and Lock User]

第三题, 上面精简坏了, 实际上还是第一个好, 没必要把代码写那么复杂：

def str2float(s):
    """字符串转浮点型"""

    def char2num(c):
        """字符转数字"""

        digists = {'0':0, '1':1, '2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9}
        return digists[c]

    s_split = s.split('.')

    pro_num = reduce(lambda x, y: x * 10 + y, map(char2num, s_split[0]))  # 获得整数部分
    sub_num = reduce((lambda x, y: x * 0.1 + y) * 0.1, map(char2num, s_split[1][::-1]))  # 获得小数部分
    return pro_num + sub_num

onespringday_xx

#4 Created at ... [Delete] [Delete and Lock User]

这个有点看不懂，s_split[1][::-1]是什么意思，我看切片部分没有看到这样的写法

努力吧咚咚锵

#5 Created at ... [Delete] [Delete and Lock User]

第一题

def normalize(name):    return str.lower(name)L1 = ['adam', 'LISA', 'barT']L2 = list(map(normalize, L1))print(L2)

非诚勿扰74685

#6 Created at ... [Delete] [Delete and Lock User]

s_split[1][::-1]是先索引再翻转，并不是切片，切片是[:x]这样的形式。希望4楼的兄弟能看到

  • 1

Reply