m = b*b-4*a*c
if m<0:
print('无解')
else:
x1 = (b*(-1)+math.sqrt(m))/(2*a)
x2 = (b*(-1)-math.sqrt(m))/(2*a)
return x1,x2
Sign in to make a reply
一点江山丶
m = b*b-4*a*c
if m<0:
print('无解')
else:
x1 = (b*(-1)+math.sqrt(m))/(2*a)
x2 = (b*(-1)-math.sqrt(m))/(2*a)
return x1,x2