一切的错误都是因为不熟练...加油

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#1 Created at ... [Delete] [Delete and Lock User]

import math#调用math

def quadratic(a, b, c):

m=b**2-4*a*c

if not isinstance(a+b+c, (int,float)):

raise TypeError('error type')

elif m<=0:

return '无解'

else:

x1=(-b+math.sqrt(b**2-4*a*c))/(2*a)

x2=(-b-math.sqrt(b**2-4*a*c))/(2*a)

return x1,x2

x=quadratic(2, 4, 1)

# 测试:

print('quadratic(2, 3, 1) =', quadratic(2, 3, 1))

print('quadratic(1, 3, -4) =', quadratic(1, 3, -4))

if quadratic(2, 3, 1) != (-0.5, -1.0):

print('测试失败')

elif quadratic(1, 3, -4) != (1.0, -4.0):

print('测试失败')

else:

print('测试成功')

#2 Created at ... [Delete] [Delete and Lock User]

当m=0时，并非无解，只是两个解相等。