if b**2-4*a*c<0:
return '无解！'
x1=(-b+math.sqrt(b**2-4*a*c))/(2*a)
x2=(-b-math.sqrt(b**2-4*a*c))/(2*a)
return x1,x2
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琪琪妈妈0512
if b**2-4*a*c<0:
return '无解！'
x1=(-b+math.sqrt(b**2-4*a*c))/(2*a)
x2=(-b-math.sqrt(b**2-4*a*c))/(2*a)
return x1,x2