对比下来,我的最复杂
n = 0
for i in range(len(s)):
print('i=%d' %i)
if s[i] == ' ':
n = n+1
else:
break
print('n=%d' %n)
m=0
print('i1=%d' %i)
if s[len(s)-(m+1)] == ' ':
m = m+1
print('m=%d' %m)
print('s number is %d' %len(s))
print(s[n:len(s)-m])
s = s[n:len(s)-m]
return s
Sign in to make a reply
用户6322136165
对比下来,我的最复杂
n = 0
for i in range(len(s)):
print('i=%d' %i)
if s[i] == ' ':
n = n+1
else:
break
print('n=%d' %n)
m=0
for i in range(len(s)):
print('i1=%d' %i)
if s[len(s)-(m+1)] == ' ':
m = m+1
else:
break
print('m=%d' %m)
print('s number is %d' %len(s))
print(s[n:len(s)-m])
s = s[n:len(s)-m]
return s