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快没时间啦

#1 Created at ... [Delete] [Delete and Lock User] 
def is_palindrome(n):
    s = str(n)
    for i in range(len(s)//2):
        if s[i] != s[-i-1]:
            return False
    return True

Eugene0_0

#2 Created at ... [Delete] [Delete and Lock User]

会漏掉个位数

快没时间啦

#3 Created at ... [Delete] [Delete and Lock User]

```

def is_palindrome(n):

    return str(n) == str(n)[::-1]

```

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