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第三题答案

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顾西瓜哇咔咔

#1 Created at ... [Delete] [Delete and Lock User]

def str2float(s)： DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9} n = 0 while(s[n] != '.'): n = n + 1

def char2num(s):
    return DIGITS[s]

def fn(x, y):
    return x*10+y

return reduce(fn, map(char2num, s[:n]))+reduce(fn, map(char2num, s[n+1:]))/10**(len(s)-n-1)

负者歌余途

#2 Created at ... [Delete] [Delete and Lock User]

兄弟 你真是个天才 吾等初学者的楷模

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