sorted by_name & by_score

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#1 Created at ... [Delete] [Delete and Lock User]

def by_name(t):
    return t[0].lower()

def by_score(t):
    return -t[1]

#2 Created at ... [Delete] [Delete and Lock User]

第一题无法处理第一个字母相同的，正常第一位相同应该按照第二位排列。