嵌套的列表内的内容可不可以直接删除？怎么删？

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#1 Created at ... [Delete] [Delete and Lock User]

L = [['Apple','Google','Microsoft'],['Java','Python','Ruby','PHP'],['Adam','Bart','Lisa']]

比如我想直接删除Java 怎么删除？pop可以删除吗？

#2 Created at ... [Delete] [Delete and Lock User]

可以，是一样的。比如老师的例子

t = ('a', 'b', ['A', 'B'])

删除'B'

t[2].pop()

#3 Created at ... [Delete] [Delete and Lock User]

L(1).pop(0)

#4 Created at ... [Delete] [Delete and Lock User]

L[1].pop(0)