dt = bb - 4ac if dt >= 0: x1 = (-b + math.sqrt(dt)) / (2a)#注意括号 x2 = (-b - math.sqrt(dt)) / (2*a) return x1, x2 else: return
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LQA爱笑的眼睛
dt = bb - 4ac if dt >= 0: x1 = (-b + math.sqrt(dt)) / (2a)#注意括号 x2 = (-b - math.sqrt(dt)) / (2*a) return x1, x2 else: return