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测试成功,

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lyingaloneiii

#1 Created at ... [Delete] [Delete and Lock User]

import math

def quadratic(a, b, c):

if (b*b-4*a*c) < 0 :
    print('number error')
else:
    delt = math.sqrt(b*b-4*a*c)
    x1 = ((-b + delt)/(2*a))
    x2 = ((-b - delt)/(2*a))
    return x1,x2

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