第一题：
def normalize(name): a = name.capitalize() return a
第二题：
def prod(L): def a(x,y): return x*y b = reduce(a,L) return b
第三题： DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9,'.':'.'} def char2num(a): return DIGITS[a] def intsum(x,y): return x10+y def floatsum(m,n): return m0.1+n def fn(L): for i in range(len(L)): if L[i] == '.': dot = i int1 = L[0:dot] float1 = L[:dot:-1] int2 = reduce(intsum,int1) float2 = reduce(floatsum,float1) whole = int2+float2*0.1 return whole L1 = list(map(char2num,s)) return fn(L1)
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IM_Dull
第一题：
def normalize(name): a = name.capitalize() return a
第二题：
def prod(L): def a(x,y): return x*y b = reduce(a,L) return b
第三题： DIGITS = {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9,'.':'.'} def char2num(a): return DIGITS[a] def intsum(x,y): return x10+y def floatsum(m,n): return m0.1+n def fn(L): for i in range(len(L)): if L[i] == '.': dot = i int1 = L[0:dot] float1 = L[:dot:-1] int2 = reduce(intsum,int1) float2 = reduce(floatsum,float1) whole = int2+float2*0.1 return whole L1 = list(map(char2num,s)) return fn(L1)