ch1
Topic sourcedic= {'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9} n=0 for x in s:
if x == '.':
s=s[:n]+s[n+1:]
break
n = n+1
n=(len(s)-n)*-1
print(n)
def c(x):
return dic[x]
def fn(x,y):
return x*10+y
return reduce(fn,map(c,s))*pow(10,n)
- 1
捣麝成尘拗莲做寸
def normalize(name):