3: from functools import reduce dict1={'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9}
def find (s): n=s.index(".") t=len(s) s=s[0:n]+s[n+1:] def aa(s): return dict1[s] return (reduce(lambda x,y:x10+y,map(aa,s)))/(10*(t-n-1))
Sign in to make a reply
Solo_Travel
3: from functools import reduce dict1={'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9}
def find (s): n=s.index(".") t=len(s) s=s[0:n]+s[n+1:] def aa(s): return dict1[s] return (reduce(lambda x,y:x10+y,map(aa,s)))/(10*(t-n-1))