参考了楼下同学的思路，lambda真的好用，●▽●，代码已验证 from functools import reduce def s2f(s): digits={'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9} def s2n(s): return digits[s] s1,s2=s.split('.') return reduce(lambda x,y:x10+y,map(s2n,s1))+reduce(lambda x,y:x0.1+y,map(s2n,s2[::-1]))*0.1
很妙啊。长知识了
这个map(s2n,s2[::-1])学到了，逆向遍历还可以这么写
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难道没有一个没人注册的ID
参考了楼下同学的思路，lambda真的好用，●▽●，代码已验证 from functools import reduce def s2f(s): digits={'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9} def s2n(s): return digits[s] s1,s2=s.split('.') return reduce(lambda x,y:x10+y,map(s2n,s1))+reduce(lambda x,y:x0.1+y,map(s2n,s2[::-1]))*0.1