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第三题,我的多定义一个求幂函数pow()

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Lyuynn

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-- coding: utf-8 --

def str2float(s): from functools import reduce digits = {'0':0,'1':1,'2':2,'3':3,'4':4,'5':5,'6':6,'7':7,'8':8,'9':9} s = s.split('.') def char2num(l): return digits[l] def fm(x,y): return x 10 + y def pow(m,n): sum = 1 i = 0 while i < n: sum = m sum i = i + 1 return sum return reduce(fm,map(char2num,s[0]))+reduce(fm,map(char2num,s[1]))/pow(10.0,len(s[1]))


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