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#1 Created at ... [Delete] [Delete and Lock User] 
# _*_ coding: utf-8 _*_

def is_palindrome(n):
    n = str(n)
    if len(n) < 2:
        return True
    if n[0] == n[-1]:
        return is_palindrome(n[1:-1])
    else:
        return False

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#2 Created at ... [Delete] [Delete and Lock User]

def is_palindrome(n): n = str(n) if len(n) < 2: return True if n[0] == n[-1]: return n #这里可以简化 else: return False

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