#判断回文,1.整数转字符串2.字符串反转3.比较 def is_palindrome(n): s1 = str(n) s2 = s1[::-1] return s1 == s2
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#判断回文,1.整数转字符串2.字符串反转3.比较 def is_palindrome(n): s1 = str(n) s2 = s1[::-1] return s1 == s2