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def is_palindrome(n): s = str(n) return s == s[::-1]

SEVEN_SE_CC

#2 Created at ... [Delete] [Delete and Lock User]

写的真好,评论里最简洁的代码

但老湿

#3 Created at ... [Delete] [Delete and Lock User]

太厉害了~6666666666666666666

但老湿

#4 Created at ... [Delete] [Delete and Lock User]
def ispa(n):
    s = str(n)
   return s == s[::-1]

圈我干啥

#5 Created at ... [Delete] [Delete and Lock User]

要求用filter函数实现

晴天菜鸟

#6 Created at ... [Delete] [Delete and Lock User]

想到一起了

def is_palindrome(n):
    return str(n)==str(n)[::-1]

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