松霜杨雪

#1 Created at ... [Delete] [Delete and Lock User]

def createCounter(): fs = [0] def counter(): fs[0] = fs[0] + 1 return fs[0] return counter

测试:

counterA = createCounter() print(counterA(), counterA(), counterA(), counterA(), counterA()) # 1 2 3 4 5 counterB = createCounter() if [counterB(), counterB(), counterB(), counterB()] == [1, 2, 3, 4]: print('测试通过!') else: print('测试失败!')

安天牛

#2 Created at ... [Delete] [Delete and Lock User]

666，巧妙利用了[]作为参数的特性

是我_也不是我

#3 Created at ... [Delete] [Delete and Lock User]

如果将这里的列表改为数字，如下 def createCounter(): fs = 0 def counter(): fs = fs + 1 return fs return counter 就会报一个UnboundLocalError: local variable 'fs' referenced before assignment的错误。有大神可以解释一下为什么将列表换成普通数字就不行了，这里不是特别明白。