Discuss / Python / 交作业,还是filter那一节比较难

交作业,还是filter那一节比较难

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trend81

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def by_name(t): return t[0].lower()

def by_score(t): return t[1]

#key指定的函数将作用于list的每一个元素上,并根据key函数返回的结果进行排序

L2 = sorted(L, key=by_name) print(L2)

L2 = sorted(L, key=by_score) print(L2)


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