#第二题： from functools import reduce def prod(L): def m(x, y): return x y out=reduce(m,L) return out print('3 5 7 9 =', prod([3, 5, 7, 9])) if prod([3, 5, 7, 9]) == 945: print('测试成功!') else: print('测试失败!')
#第三题： from functools import reduce def str2float(s): n=s.index('.') m=len(s) s=list(s) s.remove('.') u=10*(m-n-1) def char2num(s): return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[s] def fn(x,y): return x 10 + y return (reduce(fn, map(char2num, s)))/u print('str2float(\'123.456\') =', str2float('123.456')) if abs(str2float('123.456') - 123.456) < 0.00001: print('测试成功!') else: print('测试失败!')
Sign in to make a reply
李李李李泽君
#第二题： from functools import reduce def prod(L): def m(x, y): return x y out=reduce(m,L) return out print('3 5 7 9 =', prod([3, 5, 7, 9])) if prod([3, 5, 7, 9]) == 945: print('测试成功!') else: print('测试失败!')
#第三题： from functools import reduce def str2float(s): n=s.index('.') m=len(s) s=list(s) s.remove('.') u=10*(m-n-1) def char2num(s): return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[s] def fn(x,y): return x 10 + y return (reduce(fn, map(char2num, s)))/u print('str2float(\'123.456\') =', str2float('123.456')) if abs(str2float('123.456') - 123.456) < 0.00001: print('测试成功!') else: print('测试失败!')