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第三题

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def str2float(s): j=0 def fn(x,y): return x10+y def f(x,y): return x0.1+y def char2num(s): return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9, '.':'.'}[s] for k in map(char2num,s): if k=='.': break else: j=j+1 a=reduce(fn,list(map(char2num,s))[:j]) b=reduce(f,sorted(list(map(char2num,s))[j+1:],reverse=True)) return a+0.1*b


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