Discuss / Python / 作业。

作业。

Topic source

-- coding: utf-8 --

def createCounter():#利用闭包返回一个计数器函数,每次调用它返回递增整数,,, n = 0 def counter(): nonlocal n n = n + 1 return n return counter counterA = createCounter() print(counterA(), counterA(), counterA(), counterA(), counterA()) # 1 2 3 4 5 counterB = createCounter() if [counterB(), counterB(), counterB(), counterB()] == [1, 2, 3, 4]: print('测试通过!') else: print('测试失败!')


  • 1

Reply