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简化

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def count():
    def f(j):
        return lambda : j * j
    return [f(i) for i in range(1,4)]
f1, f2, f3 = count()
print(f1())
print(f2())
print(f3())

孙小二wuk

#2 Created at ... [Delete] [Delete and Lock User]

def count(): return [(lambda x:(lambda : x*x))(i) for i in range(1,4)]


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