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版本一匹配邮箱

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林林1292

#1 Created at ... [Delete] [Delete and Lock User]

e = 'someone@gmail.com' m = re.match(r'^([0-9a-zA-Z.?]+)\@([0-9a-z]+).([a-z]{3})$',e) if m!=None: print('Email is ok! The Email is :',m.group(0)) else: print('Email is failed! Please check it again. Your input is:\n',e)


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