#!/usr/bin/env python3
# -*- coding: utf-8 -*-

# 请编写函数，在Sqlite中根据分数段查找指定的名字：
import os, sqlite3

db_file = os.path.join(os.path.dirname(__file__), 'test.db')
if os.path.isfile(db_file):
    os.remove(db_file)

# 初始数据:
conn = sqlite3.connect(db_file)
cursor = conn.cursor()
cursor.execute('create table user(id varchar(20) primary key, name varchar(20), score int)')
cursor.execute(r"insert into user values ('A-001', 'Adam', 95)")
cursor.execute(r"insert into user values ('A-002', 'Bart', 62)")
cursor.execute(r"insert into user values ('A-003', 'Lisa', 78)")
cursor.close()
conn.commit()
conn.close()


def get_score_in(low, high):
    # ' 返回指定分数区间的名字，按分数从低到高排序 '
    try:
        coon = sqlite3.connect('test.db')
        cursor = coon.cursor()
        cursor.execute('select name from user where score between ? and ? order by score', (low, high))
        values = cursor.fetchall()
        return [tpl[0] for tpl in values]
    finally:
        cursor.close()
        conn.close()


# 测试:
assert get_score_in(80, 95) == ['Adam'], get_score_in(80, 95)
assert get_score_in(60, 80) == ['Bart', 'Lisa'], get_score_in(60, 80)
assert get_score_in(60, 100) == ['Bart', 'Lisa', 'Adam'], get_score_in(60, 100)

print('Pass')

作业地址 https://github.com/xiajava/learn-python3