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做复杂了，切片能更简单

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贺泽芃90440

#1 Created at ... [Delete] [Delete and Lock User] 
    L = str(n)
    a = len(L)
    b = 0
    for i in range(a):
        if L[i] == L[a-i-1]:
            b += 1
    return a == b
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