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char2num这里可以使用ord(char) - 48

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lubang03

#1 Created at ... [Delete] [Delete and Lock User]

比例子中更为简单，而且更方便改为lamda表达式

def char2num(s):
    return ord(s) - 48

lubang03

#2 Created at ... [Delete] [Delete and Lock User]

第三题我的解法，还是使用上面例子中的str2int方法

from functools import reduce
import math

def fn(x,y):
    return x*10 + y

def char2num(s):
    return ord(s) - 48

def str2int(s):
    return reduce(lambda x,y: x*10 + y, map(lambda c:ord(c) - 48,s))

def str2float(s):    
    L = s.split('.')
    return reduce(lambda s1,s2: str2int(s1) + str2int(s2) / math.pow(10,len(s2)), L)

print('str2float(\'123.456\') =', str2float('123.456'))
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