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我只洗碗不吃饭_297

#1 Created at ... [Delete] [Delete and Lock User]

!/usr/bin/env python3

-- coding: utf-8 --

计算一元二次方程的两个解

import math

def quadratic(a, b, c): flag = (b b) - (4 a c) if flag >=0: x1 = (-b + math.sqrt(flag)) / (2a) x2 = (-b - math.sqrt(flag)) / (2*a) else: return '方程式无解'

return x1,x2

print(quadratic(2,3,1)) print(quadratic(1,3,-4))

我只洗碗不吃饭_297

#2 Created at ... [Delete] [Delete and Lock User]

!/usr/bin/env python3

-- coding: utf-8 --

计算一元二次方程的两个解

import math

def quadratic(a, b, c): flag = (b b) - (4 a c) if flag >=0: x1 = (-b + math.sqrt(flag)) / (2a) x2 = (-b - math.sqrt(flag)) / (2*a) return x1, x2 else: return '方程式无解'

print(quadratic(2,3,1)) print(quadratic(1,3,-4))

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