filter的一个疑问

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#1 Created at ... [Delete] [Delete and Lock User]

针对老师的例子用了lambda，但是并没有设定x%2 ==1,就成功取出了单数，这个是什么原理，望各位大佬解答。

m = [1,2,4,5,6,9,10,15]
d=filter(lambda x:x%2,m)
for i in d:
    print(i)

#打印如下：
1
5
9
15

#2 Created at ... [Delete] [Delete and Lock User]

filter用if判断：

if x % 2 相当于 if x % 2 != 0

#3 Created at ... [Delete] [Delete and Lock User]

filter()原本的样子是：filter(函数名，iterable)iterab，简单点说就是一一筛选出1或者True的值............小白的回答

#4 Created at ... [Delete] [Delete and Lock User]

是filter（函数名，iterable）