实现是实现了,但是感觉自己做的好烂
from functools import reduce def str2float(s): s=list(s) b = len(s) - s.index('.')-1 s.pop(s.index('.')) n = 1 while b>0: n = n*10 b -=1 def char2num(s): return {'0':0, '1':1, '2':2, '3':3, '4':4, '5':5, '6':6, '7':7, '8':8, '9':9}[s] return float(reduce(lambda x, y: x*10 + y, map(char2num,s))/n) print('str2float(\'12.553456.\')=', str2float('12.553456'))
Sign in to make a reply
Nicktimebreak
实现是实现了,但是感觉自己做的好烂