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第三题

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def prod(s): def char2flo(s): return {'0': 0, '1': 1, '2': 2, '3': 3, '4': 4, '5': 5, '6': 6, '7': 7, '8': 8, '9': 9}[s] a=s.index(".") s1=s[:a] s2=s[len(s):a:-1] return (reduce(lambda x,y:x10+y,map(char2flo,s1)))+(0.1reduce(lambda x,y:x*0.1+y,map(char2flo,s2)))


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