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膜拜大神的一行代码

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九_努力成为BetterMe

#1 Created at ... [Delete] [Delete and Lock User] 
def is_palindrome(n):
    return str(n) == str(n)[::-1]

直接用str可以将整数转化为字符串，然后切片比较。

  1. 切片的使用；
  2. 字符也可以直接用==比较。

偶一5我

#2 Created at ... [Delete] [Delete and Lock User]

性能不行。

用户5124488730

#3 Created at ... [Delete] [Delete and Lock User]

你这个最简洁，比我的强.

在此插入代码

def str_sym(s): #字符串是否对称 n = len(s) b = True i = 0 while i < n: b = b*(s[i]==s[-(i+1)]) i = i +1 return b

def ispalindrome(n): str_n = str(n) # int转换成字符串 return str_sym(str_n)

output = filter(ispalindrome, range(1,1000)) print(list(output))

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